1964
DOI: 10.1007/bf01897027
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Kreislagerungen auf Flächen konstanter Krümmung

Abstract: In der euklidischen Ebene ist die Dichte 1 einer aus kongruenten Kreisen bestehenden Packung bzw. i]lberdeckung bekanntlich 7~ d<_--bzw. 27z D---->~ 9 Diese beiden Ungleichungen lassen sich im folgenden allgemeineren, yon L. FEJES T6T~ herriihrenden Satz vereinigen. 2 Es sei {Ki} ein System kongruenter Kreise mit der vorgegebenen Dichte <_-(5 <-. Das DeckungsmaB yon {K,} beztiglich der euklidischen Ebene erreicht sein Maximum, wenn die Kreismittelpunkte die Ecken eines regulgren Dreiecksmosaiks sind. Das Decku… Show more

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Cited by 16 publications
(6 citation statements)
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“…Our first aim is to give affirmative answers to both of these questions (Theorem 1 and Remark 2). As a corollary we obtain a result due to Imre [6]. Theorem 1 will imply that if \J/ is convex then a regular hexagonal arrangement is optimal for the plane (Theorem 3).…”
Section: Introductionmentioning
confidence: 71%
“…Our first aim is to give affirmative answers to both of these questions (Theorem 1 and Remark 2). As a corollary we obtain a result due to Imre [6]. Theorem 1 will imply that if \J/ is convex then a regular hexagonal arrangement is optimal for the plane (Theorem 3).…”
Section: Introductionmentioning
confidence: 71%
“…Fejes Tóth proved his estimate first for the 2-sphere and then only for E 2 , see [4,5]. Alternative proofs, in some cases for surfaces of constant curvature, are due to L. Fejes Tóth [6], Imre [12], Bollobas and Stern [2], G. Fejes Tóth [3], Florian [7], Papadimitriou [13], and Haimovich and Magnanti [11]. An extension to Jordan measurable sets on 2-dimensional Riemannian manifolds can be obtained along the lines of [8], see Gruber [10].…”
Section: Introduction and Statement Of The Resultsmentioning
confidence: 99%
“…and hence ||d {0 }|U 0 (t/(r"A)) ^ s = e n (t/(B n )). The set of midpoints r n a n satisfies |K«aJU 0 (i/(B»)) = ll d {o}IU 0 (i/(r n >i))-Therefore, e n (^(B n )) = ||d { o } || Mt /(r n >i)) (4)(5)(6)(7)(8)(9)(10)(11)(12)(13)(14) and r"a n € tf n (U{B n )). It follows from Lemma 2.4 and (4.13) that This implies…”
Section: U{b N )(D P ^ E) < U(r N A){d {0}mentioning
confidence: 99%
“…According to an inequality obtained in [14] (see also For n > 1, choose a e ^n{P)-If P{da < e n } = 1, let 7 = Uaea^O-Then |7| ^ kn and {d a < e n } С {d 7 ^ e n /2}, hence…”
Section: Q(u( a )) = *L$£!imentioning
confidence: 99%