1999
DOI: 10.1307/mmj/1030132411
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Expanding factors for pseudo-Anosov homeomorphisms.

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Cited by 15 publications
(16 citation statements)
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“…Since f * 1 : H 1 (M) → H 1 (M) and a Markov matrix will have the same eigenvalues up to zeros and roots of unity [8], λ is the unique eigenvalue with largest modulus. An element of H 1 (M ) can be expressed as a linear combination of these basis elements.…”
Section: Lemma 22 There Exists a δ > 0 Such That Given Any Rectanglmentioning
confidence: 99%
“…Since f * 1 : H 1 (M) → H 1 (M) and a Markov matrix will have the same eigenvalues up to zeros and roots of unity [8], λ is the unique eigenvalue with largest modulus. An element of H 1 (M ) can be expressed as a linear combination of these basis elements.…”
Section: Lemma 22 There Exists a δ > 0 Such That Given Any Rectanglmentioning
confidence: 99%
“…The author noticed that a similar proof was given in [4]. Theorem 1.6 (Rykken [19]). Our following results are for the case when (F u , µ u ) has singularities other than unpunctured 3-pronged and punctured 1-pronged singularities.…”
Section: Resultsmentioning
confidence: 61%
“…A proof of the fact that any affine automorphism lifts can be found in [Ry,Theorem 3.2]. The statement about the number of cylinders and rectangles follows immediately from the fact that the degree of the cover is 2.…”
Section: Taking Orientation Double Covers Ismentioning
confidence: 99%