1974
DOI: 10.1017/s1446788700029190
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A note on extensions of Baer and P. P. -rings

Abstract: Communicated by B. MondBaer rings are rings in which the left (right) annihilator of each subset is generated by an idempotent [6]. Closely related to Baer rings are left P.P.-rings; these are rings in which each principal left ideal is projective, or equivalently, rings in which the left annihilator of each element is generated by an idempotent. Both Baer and P.P.-rings have been extensively studied (e.g. [7]) and it is known that both of these properties are not stable relative to the formation of polynomial… Show more

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Cited by 315 publications
(129 citation statements)
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“…Then we also consider extending the quasi-Baer ring condition from subrings without semiprime condition, but with strengthening the intersection condition. We use our results to generalise a result of Armendariz [1]. LEMMA …”
Section: Extending the Quasi-baer Conditionmentioning
confidence: 81%
See 1 more Smart Citation
“…Then we also consider extending the quasi-Baer ring condition from subrings without semiprime condition, but with strengthening the intersection condition. We use our results to generalise a result of Armendariz [1]. LEMMA …”
Section: Extending the Quasi-baer Conditionmentioning
confidence: 81%
“…[4] Conversely, let / be an ideal of R, and assume there exsits e 6 Si(R) such that / C eR and 1(1) n eR = eR(l -e). Let a € 1 (1). Then a = ae + a(l -e).…”
Section: Proposition 12 a Ring R Is Quasi-baer If And Only If Whenementioning
confidence: 99%
“…(3) Let σ be an endomorphism of a ring R with σ n (b) = b and ab = 0 for a, b ∈ R. Then we get aRb = aRσ n (b) = 0 by (2), and so R is IFP.…”
Section: Skew Ifp Ringsmentioning
confidence: 99%
“…R(A, B) is a left APP-ring, then A is a left APP-ring. But Example 3.9 (2) shows that B need not be a left APP-ring in general. Proof.…”
Section: Proposition 33 If a Is A Commutative Ring Then The Ring Rmentioning
confidence: 99%
“…Armendariz showed that polynomial rings over right PP-rings need not be right PP in the example in [2]. From [5, (1) R is left APP.…”
Section: Let T Be a Ring And Rmentioning
confidence: 99%