2015
DOI: 10.1016/j.matpr.2015.07.338
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Ti(Pt, Pd, Au) based High Temperature Shape Memory Alloys

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Cited by 37 publications
(16 citation statements)
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“…Therefore, this study investigates the effect of further Zr addition on shape recovery. A previous study also indicated that V addition drastically improved the strength of both the martensite and austenite phases 26) . Hence, the effect of V addition on the shape recovery of Ti-Pd-Zr was also investigated.…”
Section: Introductionmentioning
confidence: 76%
See 1 more Smart Citation
“…Therefore, this study investigates the effect of further Zr addition on shape recovery. A previous study also indicated that V addition drastically improved the strength of both the martensite and austenite phases 26) . Hence, the effect of V addition on the shape recovery of Ti-Pd-Zr was also investigated.…”
Section: Introductionmentioning
confidence: 76%
“…In our previous study, we focused on the addition of different alloying elements into TiPd to improve its strength, of which Zr was found to be the most promising alloying element [26][27][28] . For example, the addition of 5 at% Zr to TiPd improved the shape recovery ratio from 13% in the TiPd binary alloy to 94% after being tested at 380 C 28) .…”
Section: Introductionmentioning
confidence: 99%
“…The current author has published a number of papers related to nickel-free titanium based shape memory alloys for biomedical and engineering applications in international journals [78][79][80][81][82][83][84][85][86]. During postdoctoral work from 2012 to 2014 in the High Temperature Materials Unit, National Institute for Materials Science (NIMS), Tsukuba, Japan, the current author's research activities were related to TiPt and TiAu based intermetallics for high temperature applications and he has published papers in international journals [87][88][89][90][91][92][93][94].…”
Section: Biocompatibility Issues Of Nitinolmentioning
confidence: 99%
“…It has been also reported that the equiatomic TiPd alloy has a shape recovery ratio of about 60%, using the following equation: shape recovery ratio = (L" − L')/ (L' − L 0 ) × 100, where is L 0 : initial length of sample, L': deformed sample length, and L": recovered sample length. Moreover, the shape recovery ratio improves with the addition of a third element [4,5]. In addition, Sato et al reported that a complete shape recovery was achieved by the effect of a training process, that is, a repeated isobaric test on the Ti-Pd-Zr alloy [6].…”
Section: Introductionmentioning
confidence: 99%