“…If the structure is optically thin in this direction then its emissivity is ε = kd 1, where k = σ p p + σ n n is the absorption coefficient, d is the thickness along y, n and p are the free electron and hole concentrations, σ n , σ p are the cross sections of absorption by free electrons and holes, respectively. The spectral radiation density under such conditions is proportional to the concentration of carriers [6,7]. For simplicity, one may also neglect contribution of electrons to emissivity because their absorption cross section in the considered spectral range is small as compared to holes.…”