1971
DOI: 10.2307/2037989
|View full text |Cite
|
Sign up to set email alerts
|

The Norm of a Hermitian Element in a Banach Algebra

Abstract: Abstract.We prove that the norm of a hermitian element in a Banach algebra is equal to the spectral radius of the element.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
12
0

Year Published

1984
1984
2021
2021

Publication Types

Select...
6
2

Relationship

0
8

Authors

Journals

citations
Cited by 10 publications
(12 citation statements)
references
References 1 publication
0
12
0
Order By: Relevance
“…For example, if T is a Hermitian operator, then T = r(T ), where r(T ) is the spectral radius of T . This was proved by Browder [7], Katznelson [14] and Sinclair [23]. All the three proofs depend on Bernstein's inequality.…”
Section: An Operator T ∈ B(x) Is Said To Be Hermitian If V (T ) Is Rementioning
confidence: 87%
“…For example, if T is a Hermitian operator, then T = r(T ), where r(T ) is the spectral radius of T . This was proved by Browder [7], Katznelson [14] and Sinclair [23]. All the three proofs depend on Bernstein's inequality.…”
Section: An Operator T ∈ B(x) Is Said To Be Hermitian If V (T ) Is Rementioning
confidence: 87%
“…It is well-known that the operator norm of a selfadjoint operator in a Hilbert space coincides with its spectral radius. Making use of the Bernstein inequality, Katsnelson proved in [17] the following result, which, independently (and more or less simultaneously), was also found by Browder [4] and Sinclair [39]. Theorem 4.1.…”
Section: Series Of Simple Fractionsmentioning
confidence: 77%
“…For details of this result and those quoted above the reader is referred to [7,36]. The connection between the results quoted above and partially ordered real Banach spaces is described in the next lemma.…”
Section: Lemma 22mentioning
confidence: 81%