2007
DOI: 10.1016/j.jfa.2007.02.004
|View full text |Cite
|
Sign up to set email alerts
|

Dissipative operators on Banach spaces

Abstract: A bounded linear operator T on a Banach space is said to be dissipative if e tT 1 for all t 0. We show that if T is a dissipative operator on a Banach space, then: (a) lim t→∞ e tT T = sup{|λ|: λ ∈ σ (T ) ∩ iR}. (b) If σ (T ) ∩ iR is contained in [−iπ/2, iπ/2], then lim t→∞ e tT sin T = sup | sin λ|: λ ∈ σ (T ) ∩ iR .Some related problems are also discussed.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1

Citation Types

1
2
0

Year Published

2010
2010
2021
2021

Publication Types

Select...
5
2

Relationship

2
5

Authors

Journals

citations
Cited by 7 publications
(3 citation statements)
references
References 15 publications
(15 reference statements)
1
2
0
Order By: Relevance
“…The similar result holds for polynomially bounded operators [3] (for related results see also [2,5,8,10]). We see that under the assumptions of Esterle-Strouse-Zouakia Theorem the Lebesgue measure of σ u (T ) is necessarily zero.…”
Section: Introductionsupporting
confidence: 62%
“…The similar result holds for polynomially bounded operators [3] (for related results see also [2,5,8,10]). We see that under the assumptions of Esterle-Strouse-Zouakia Theorem the Lebesgue measure of σ u (T ) is necessarily zero.…”
Section: Introductionsupporting
confidence: 62%
“…Proof of Theorem 2.11. We basically follow the proof in [14,Lemma 3.4]. Let a > 0 be such that iσ T (x) ⊂ (−a, a) .…”
Section: The Resultsmentioning
confidence: 98%
“…Note that in the preceding lemma, the weight function ω Proof. We basically follow the proof of Lemma 3.4 in [12]. Let an arbitrary a > r T (x) be fixed.…”
Section: The Norm Of the Commutator At − T Amentioning
confidence: 99%