2018
DOI: 10.1002/jgt.22369
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The homomorphism threshold of ‐free graphs

Abstract: We determine the structure of {C3,C5}‐free graphs with n vertices and minimum degree larger than n/5: such graphs are homomorphic to the graph obtained from a (5k−3)‐cycle by adding all chords of length 1(mod5), for some k. This answers a question of Messuti and Schacht. We deduce that the homomorphism threshold of {C3,C5}‐free graphs is 1/5, thus answering a question of Oberkampf and Schacht.

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Cited by 12 publications
(15 citation statements)
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“…, C 2k+1 } of odd cycles of length at most 2k + 1. We remark that for these families the homomorphism threshold was obtained and in [4,10] it was shown that δ hom (C 2k+1 ) = 1/(2k + 1).…”
Section: Homomorphism Thresholds Of Graphsmentioning
confidence: 81%
See 1 more Smart Citation
“…, C 2k+1 } of odd cycles of length at most 2k + 1. We remark that for these families the homomorphism threshold was obtained and in [4,10] it was shown that δ hom (C 2k+1 ) = 1/(2k + 1).…”
Section: Homomorphism Thresholds Of Graphsmentioning
confidence: 81%
“…In particular, the case of odd cycles of length at least five seems to be an interesting open case. Very recently, in [4,10] an upper bound of the form…”
Section: Homomorphism Thresholds Of Graphsmentioning
confidence: 99%
“…Analogous to the relation between Conjecture and Theorem one may wonder if every (12,12(2k+1)2)‐dense graph contains an odd cycle of length at most 2k1. Letzter and Snyder showed that a graph G on n vertices with δfalse(Gfalse)>n5 and odd‐girth at least seven is homomorphic to Fk3, for some k . Therefore combining this result with Theorem we get the following.…”
Section: Introductionmentioning
confidence: 99%
“…Note that for k " 2 part (ii ) of Theorem 1.2 would include part (i ) and this is Łuczak's theorem [13]. For k " 3 Theorem 1.2 was obtained by Letzter and Snyder [12]. We remark that our approach substantially differs from the work of Łuczak and of Letzter and Snyder.…”
mentioning
confidence: 88%
“…A first step of generalising Łuczak's result by viewing K 3 as the shortest odd cycle, was recently undertaken by Letzter and Snyder [12] by showing δ hom pC 5 q ď 1 5 and δ hom ptC 3 , C 5 uq " 1 5 .…”
mentioning
confidence: 99%