2011
DOI: 10.1080/03081080903346425
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The Cauchy interlacing theorem in simple Euclidean Jordan algebras and some consequences

Abstract: In this article, based on the min-max theorem of Hirzebruch, we formulate and prove the Cauchy interlacing theorem in simple Euclidean Jordan algebras. As a consequence , we relate the inertias of an element and its principal components and extend some well known matrix theory theorems and inequalities to the setting of simple Euclidean Jordan algebras.

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Cited by 34 publications
(29 citation statements)
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“…Hence, the first inequality in (11) becomes equality by Corollary 4.10 in [5] and the last inequality in (11) becomes equality as λ ↓ i (x) = 1 a p/q tr,p (λ ↓ i (a)) p−1 . Hence, a, x = a tr,p .…”
Section: Theorem 41 (Spectral Minkowski Inequality) Let V Be Any Eumentioning
confidence: 87%
See 1 more Smart Citation
“…Hence, the first inequality in (11) becomes equality by Corollary 4.10 in [5] and the last inequality in (11) becomes equality as λ ↓ i (x) = 1 a p/q tr,p (λ ↓ i (a)) p−1 . Hence, a, x = a tr,p .…”
Section: Theorem 41 (Spectral Minkowski Inequality) Let V Be Any Eumentioning
confidence: 87%
“…Then two inequalities in (11) become equalities. Thus, a and x operator commute by Corollary 4.10 in [5] as the first equality in (11) and λ ↓ i (x) = c(λ ↓ i (a)) p−1 for some positive number c as the second equality in (11). Since a and x operator commute, there exists a Jordan frame {e 1 , e 2 , .…”
Section: Theorem 41 (Spectral Minkowski Inequality) Let V Be Any Eumentioning
confidence: 90%
“…It has been observed in [10] that in a simple algebra of rank r , the following Minkowski type inequality holds for all x, y ≥ 0:…”
Section: Corollary 4 (A Bergstrom Type Inequality) Let X Y U and P mentioning
confidence: 99%
“…where a := An analogous result holds in any Euclidean Jordan algebra [10]: If x ≥ 0 in J with Peirce decomposition x = i≤j x ij with respect to any Jordan frame {e 1 , e 2 , . .…”
Section: Theorem 4 Suppose Thatmentioning
confidence: 99%
“…. , r. Since these are the "leading principal minors" of x, by Problem 5, VI.4 in [6] or Corollary 4.5 in [10], x > 0. ⊓ ⊔…”
Section: It Follows That (M/a)/(u/a) = M/u This Completes the Proofmentioning
confidence: 99%