Abstract:1. The application of the geometrical properties of the Brocard and Tucker circles of a triangle to a quadrilateral appears never to have been adequately worked out, as far as the author can discover. Hence, the object of this paper.Some of the problems involved have been published, under the author's name, as independent questions for solution, and where, in the author's opinion, solutions other than his own have seemed more satisfactory for the logical treatment of the subject, these solutions have been empl… Show more
“…Theorem 9 Let P i 1 and P i 2 be Brocard points of the quadrangle A i B i C i D i , i = 1, 2. Then the second Brocard point P 1 2 of the quadrangle A 1 B 1 C 1 D 1 coincides with P 1 , while the first Brocard point P 2 1 of the quadrangle A 2 B 2 C 2 D 2 coincides with P 2 .…”
Section: Proof Let Us Prove Thatmentioning
confidence: 95%
“…The Euclidean case of Theorem 2 can be found in [1], and the Euclidean analogue of Theorem 3 is stated in [2] and [4].…”
Section: Brocard Pointsmentioning
confidence: 99%
“…According to [3] (Theorem 4, for h = −2k), the line AP 1 has the equation y = (a + b + 2k)x − a(2k + b). Hence, A 1 has coordinates b + 2k, (b + 2k) 2 . Similarly, we get the other intersections:…”
Section: Brocard Pointsmentioning
confidence: 99%
“…, sides (1) and tangents of its circumscribed circle y = x 2 at its vertices are given by (2). These are the equivalent statements:…”
U radu se prikazuju neki novi rezultati o Brocardovim točkama harmoničnog četverokuta u izotropnoj ravnini. Konstruiraju se novi harmonični četverokuti pridruženi danom četverokutu, te se proučavaju njihova svojstva vezana uz Brocardove točke.
“…Theorem 9 Let P i 1 and P i 2 be Brocard points of the quadrangle A i B i C i D i , i = 1, 2. Then the second Brocard point P 1 2 of the quadrangle A 1 B 1 C 1 D 1 coincides with P 1 , while the first Brocard point P 2 1 of the quadrangle A 2 B 2 C 2 D 2 coincides with P 2 .…”
Section: Proof Let Us Prove Thatmentioning
confidence: 95%
“…The Euclidean case of Theorem 2 can be found in [1], and the Euclidean analogue of Theorem 3 is stated in [2] and [4].…”
Section: Brocard Pointsmentioning
confidence: 99%
“…According to [3] (Theorem 4, for h = −2k), the line AP 1 has the equation y = (a + b + 2k)x − a(2k + b). Hence, A 1 has coordinates b + 2k, (b + 2k) 2 . Similarly, we get the other intersections:…”
Section: Brocard Pointsmentioning
confidence: 99%
“…, sides (1) and tangents of its circumscribed circle y = x 2 at its vertices are given by (2). These are the equivalent statements:…”
U radu se prikazuju neki novi rezultati o Brocardovim točkama harmoničnog četverokuta u izotropnoj ravnini. Konstruiraju se novi harmonični četverokuti pridruženi danom četverokutu, te se proučavaju njihova svojstva vezana uz Brocardove točke.
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