“…67 A diplumbylene is formed in the reaction of potassium {1,1,4,4,-(SiMe 3 ) 4 -2,2,3,3-(Me) 4 -tetrasilane} with lead(II) bromide in the presence of triethylphosphine, giving initially [{1,1,4,4,-(SiMe 3 ) 4 -2,2,3,3-(Me) 4 -tetrasilane}]Pb(PEt 3 ) (2) that loses the phosphine upon reaction with Massey's (perfluoro)triphenylboron to produce the dimer ([{1,1,4,4,-(SiMe 3 ) 4 -2,2,3,3-(Me) 4 -tetrasilane}]Pb) 2 (…”