1994
DOI: 10.1017/s0269964800003454
|View full text |Cite
|
Sign up to set email alerts
|

Some Properties of the Poisson Distribution with an Application to Reliability Testing

Abstract: Construction of a certain class of component tests for verification of series system reliability requires the use of some properties of the Poisson distribution that are not commonly known or used. This paper states and proves these results.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1

Citation Types

0
3
0

Year Published

1995
1995
2002
2002

Publication Types

Select...
4
2

Relationship

2
4

Authors

Journals

citations
Cited by 10 publications
(3 citation statements)
references
References 4 publications
0
3
0
Order By: Relevance
“…This in turn requires φ m (β)/(-ln R 0 ) ≤ φ m (1-α)/(-ln R 1 ), or equivalently, (-ln R 1 )/(-ln R 0 ) ≤ φ m (1-α)/φ m (β). Since R 1 >R 0 the LHS of this last inequality is strictly less than 1, and it has been shown [13] that if α+β<1 as assumed, the ratio in the RHS is strictly increasing in m and approaches 1 as m approaches ∞. Therefore we can find t 1 ,t 2 ,...,t n that satisfy (12) and (13) for all m≥m * where m * is defined as…”
Section: A Component Test Plan For the Weibull Distributionmentioning
confidence: 89%
See 1 more Smart Citation
“…This in turn requires φ m (β)/(-ln R 0 ) ≤ φ m (1-α)/(-ln R 1 ), or equivalently, (-ln R 1 )/(-ln R 0 ) ≤ φ m (1-α)/φ m (β). Since R 1 >R 0 the LHS of this last inequality is strictly less than 1, and it has been shown [13] that if α+β<1 as assumed, the ratio in the RHS is strictly increasing in m and approaches 1 as m approaches ∞. Therefore we can find t 1 ,t 2 ,...,t n that satisfy (12) and (13) for all m≥m * where m * is defined as…”
Section: A Component Test Plan For the Weibull Distributionmentioning
confidence: 89%
“…It is clear that for both (12) and (13) to be satisfied m should satisfy B(m)≤A(m). This in turn requires φ m (β)/(-ln R 0 ) ≤ φ m (1-α)/(-ln R 1 ), or equivalently, (-ln R 1 )/(-ln R 0 ) ≤ φ m (1-α)/φ m (β).…”
Section: A Component Test Plan For the Weibull Distributionmentioning
confidence: 99%
“…The LHS of this last inequality is strictly less than 1, and it has been shown by Rajgopal et al [17] that as long as a b`1, the ratio in the RHS is strictly increasing in m and approaches 1 as m approaches I. Thus, the problem is feasible for all m !…”
Section: No Prior Informationmentioning
confidence: 93%