Slip bands in metallic glasses

Zielinski, P.G.; Ast, D. G.

doi:10.1080/01418618308236546

Cited by 35 publications

(19 citation statements)

References 18 publications

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“…The larger the amount of shear in the glass the more pronounced is the localization of deformation in the crystalline phase. Measurements of the shear offsets using SEM images give larger values, from 500 nm 13 up to 2 m. 6 Also, the shear displacement, which we measured in TEM in the specimens deformed in a bulk form, is around 150 nm. This result again indicates the influence of the film thickness on the dimensions of the shear bands.…”

Section: Amount Of Shearmentioning

confidence: 98%

“…Deformation mechanisms of metallic glasses attracted a lot of attention from both theoretical and experimental sides. [4][5][6][7][8][9][10] Most of the experimental work, however, was done using scanning electron microscopy (SEM). Transmission electron microscopy (TEM) studies of shear bands were not very successful so far due to the relatively small structural changes in the shear bands, frequently undetectable by TEM.…”

Section: Introductionmentioning

confidence: 99%

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In situ transmission electron microscopy studies of shear bands in a bulk metallic glass based composite

2001

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In situ straining transmission electron microscopy (TEM) experiments were performed to study the propagation of the shear bands in the Zr 56.3 Ti 13.8 Cu 6.9 Ni 5.6 Nb 5.0 Be 12.5 bulk metallic glass based composite. Contrast in TEM images produced by shear bands in metallic glass and quantitative parameters of the shear bands were analyzed. It was determined that, at a large amount of shear in the glass, the localization of deformation occurs in the crystalline phase, where formation of dislocations within the narrow bands are observed.

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Section: Amount Of Shearmentioning

confidence: 98%

Section: Introductionmentioning

confidence: 99%

In situ transmission electron microscopy studies of shear bands in a bulk metallic glass based composite

2001

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“…Plastic deformation of metallic glasses (MG) at temperatures much lower than the glass transition temperature Tg is realized via inhomogeneous shear in narrow shear bands [1,2]. Conditions of the shear bands creation and resulting MG failure during tensile test have been studied for a longer time.…”

Section: Introductionmentioning

confidence: 99%

Low temperature and strain rate dependence of fracture stress and fracture toughness on thin Fe40Ni40B20 amorphous ribbon

Ocelík¹,

Bengus²,

Korolkova³

et al. 1991

J Mater Sci

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“…Such shear fracture behavior has been widely observed in many metallic glasses, as summarized in the literatures [3,4] and Table 1. [5][6][7][8][9][10][11][12][13][14] According to the definition in the textbooks, [1,2] the tensile fracture strength of the metallic glass should be equal to r T =F max /A 0 . However, the actual area of the shear fracture surface becomes A 0 /sin(h T ) and the applied normal tensile force on the shear plane is F max cos(h T ), as shown in Figure 1.…”

mentioning

confidence: 99%

“…Which is the real tensile strength of a metallic glass, F max /A 0 or F max sin(h T )cos(h T )/A 0 ? Why do metallic glasses often fail neither along the maximum normal stress plane (h T =90°) nor along the maximum shear stress plane (h T =45°) under tensile loading [5][6][7][8][9][10][11][12][13][14] ? What is the physical nature of the materials strength?…”

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confidence: 99%

The Physical Nature of Materials Strengths

Zhang

Eckert

2007

Adv Eng Mater

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The strength of a material is assessed most often by means of a tensile test. For a given material with an original cross-section area A 0 , if the applied maximum tensile force is equal to F max , the fracture strength can be calculated by r F =F max /A 0 , as described in the textbooks. [1,2] For a bulk metallic glassy specimen, it often fails in a shear mode, as shown in Figure 1, and the shear fracture surface makes an angle of h T =56°with respect to the tension axis. Such shear fracture behavior has been widely observed in many metallic glasses, as summarized in the literatures [3,4] and Table 1. [5][6][7][8][9][10][11][12][13][14] According to the definition in the textbooks, [1,2] the tensile fracture strength of the metallic glass should be equal to r T =F max /A 0 . However, the actual area of the shear fracture surface becomes A 0 /sin(h T ) and the applied normal tensile force on the shear plane is F max cos(h T ), as shown in Figure 1. This will result in another tensile strength F max sin(h T )cos(h T )/ A 0 , which is different from that (F max /A 0 ) defined in textbooks. [1,2] Consequently, this gives rise to some interesting and significant questions. Which is the real tensile strength of a metallic glass, F max /A 0 or F max sin(h T )cos(h T )/A 0 ? Why do metallic glasses often fail neither along the maximum normal stress plane (h T =90°) nor along the maximum shear stress plane (h T =45°) under tensile loading [5][6][7][8][9][10][11][12][13][14] ? What is the physical nature of the materials strength?For a material subjected to a tensile force F, there is always a combined stress (r n ,s n ) on any plane, as illustrated in Figure 2(a). In order to better understand the physical nature of materials strength and answer the interesting questions above, we proposed that there are only two independent intrinsic strengths r 0 and s 0 for an isotropic material 4 . As illustrated in Figure 2(b), r 0 is defined as the critical strength of a material in a Mode I failure; s 0 is the critical strength of a material in a Mode II fracture. If any plane of a material is subjected to a combined stress (r n ,s n ), the tensile failure condition can be expressed by the following criterion 4 , (r n /r 0 ) 2 + (s n /s 0 ) 2 = 1.(1)Meanwhile, the tensile stress state (r n ,s n ) on any shear plane follows the Mohr-circle equation, i.e.(r n -r T /2) 2 + (s n ) 2 = (r T /2) 2 .(2)According to Equations 1 and 2, the two independent strengths, s 0 and r 0 can be derived as:Here, r T =F max /A 0 is the so-called tensile fracture strength; a is the fracture mode factor [4] and can be calculated from the macroscopic tensile shear fracture angle, see the discussion below. Here, it is suggested that r T =F max /A 0 can be only regarded as nominal fracture strength, rather than the intrin-COMMUNICATIONS ADVANCED ENGINEERING MATERIALS 2007, 9, No. 3 metallic glassy specimen. The nominal tensile fracture strength of the specimen is about 1.58 GPa and the shear fracture surface makes an angle of about 56°with respect to the t...

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Slip bands in metallic glasses

Cited by 35 publications

References 18 publications

In situ transmission electron microscopy studies of shear bands in a bulk metallic glass based composite

In situ transmission electron microscopy studies of shear bands in a bulk metallic glass based composite

Low temperature and strain rate dependence of fracture stress and fracture toughness on thin Fe40Ni40B20 amorphous ribbon

The Physical Nature of Materials Strengths

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