“…Since X is regular, each point is the intersection of the closure of countably many neighbourhoods, hence the space is first countable being countably compact. Thus, a(p, X) ≤ ω for every p ∈ X and, by [2,Corollary 5.4], X will be both Tychonoff and suborderable (in particular, pseudocompact). By [5,Theorem 3.4], X will be totally disconnected.…”