2015
DOI: 10.1016/j.jnt.2014.09.017
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Ramanujan-type congruences for overpartitions modulo 5

Abstract: Abstract. Let p(n) denote the number of overpartitions of n. Recently, Fortin-JacobMathieu and Hirschhorn-Sellers independently obtained 2-, 3-and 4-dissections of the generating function for p(n) and derived a number of congruences for p(n) modulo 4, 8 and 64 including p(5n + 2) ≡ 0 (mod 4), p(4n + 3) ≡ 0 (mod 8) and p(8n + 7) ≡ 0 (mod 64). By employing dissection techniques, Yao and Xia obtained congruences for p(n) modulo 8, 16 and 32, such as p(48n + 26) ≡ 0 (mod 8), p(24n + 17) ≡ 0 (mod 16) and p(72n+69) … Show more

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Cited by 21 publications
(16 citation statements)
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“…Hirschhorn and Sellers show p(9 α (27n + 18)) ≡ 0 (mod 3) in [10]. That p(40n + 35) ≡ 0 (mod 5) was conjectured by Hirschhorn and Sellers and proved by Chen and Xia; the more general 4 k (40n + 35) was proved by W. Y. C. Chen, Sun, Wang and Zhang very recently [4], in a paper which also includes many other congruences mod 5 for the overpartition function that can be combined with modulus 7 for c 7,1 .…”
Section: (K 1)-colored Partitionsmentioning
confidence: 97%
“…Hirschhorn and Sellers show p(9 α (27n + 18)) ≡ 0 (mod 3) in [10]. That p(40n + 35) ≡ 0 (mod 5) was conjectured by Hirschhorn and Sellers and proved by Chen and Xia; the more general 4 k (40n + 35) was proved by W. Y. C. Chen, Sun, Wang and Zhang very recently [4], in a paper which also includes many other congruences mod 5 for the overpartition function that can be combined with modulus 7 for c 7,1 .…”
Section: (K 1)-colored Partitionsmentioning
confidence: 97%
“…Lin [12] presented a new proof of Hirschhorn and Sellers' conjecture. Chen, Sun, Wang and Zhang [4] deduced various Ramanujan-type congruences modulo 5 for overpartitions. Hirschhorn and Sellers [9], and Lovejoy and Osburn [14] discovered several congruences modulo 3 forp(n).…”
mentioning
confidence: 99%
“…If we extract the terms in which the power of q is congruent to 2 modulo 5 from (4.2), divide by q 2 , and replace q 5 by q, we obtain the following result due to Chen et al [8,Eq. 3.12].…”
Section: Proofs Of Theorem 11 and Theorem 12mentioning
confidence: 98%
“…If we extract those terms in which the power of q is even and replace q 2 by q, we find that ∞ n=0 p(8n)q n ≡ 1 ϕ(−q) 8 …”
Section: Proofs Of Theorem 11 and Theorem 12mentioning
confidence: 99%
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