2005 IEEE Pulsed Power Conference 2005
DOI: 10.1109/ppc.2005.300588
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Railgun Erosion Simulator

Abstract: resulting transient emfs tend to drive the current to the Abstract center of the armature. The U.S. Army Armament Research, Development, and II. MODEL Engineering Center's Benet Laboratories is currently developing a diagnostic launcher for use as an erosion A model of the launcher is being developed as an simulator to investigate issues associated with the bore life of rail guns. The launcher being developed at Benet gm g g predicting performance. It is also being used to estimate provides as b forvliti o f n… Show more

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Cited by 2 publications
(3 citation statements)
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“…A simple axisymmetric 3D model of an armature is also used to illustrate the basic time dependent effects of induced fields on the current distributions in armatures under pulsed current conditions. The model results are consistent with our data on the formation and convergence of concentrated currents at the armature-rail interface in our laboratory firing tests [1]. A number of our firing test results and conclusions are similar to those of Drobyshevski et al [2].…”
Section: Introductionsupporting
confidence: 92%
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“…A simple axisymmetric 3D model of an armature is also used to illustrate the basic time dependent effects of induced fields on the current distributions in armatures under pulsed current conditions. The model results are consistent with our data on the formation and convergence of concentrated currents at the armature-rail interface in our laboratory firing tests [1]. A number of our firing test results and conclusions are similar to those of Drobyshevski et al [2].…”
Section: Introductionsupporting
confidence: 92%
“…For large x A /h we can neglect the end effect contributions perpendicular to the rails along h at the breech and muzzle where the perpendicular fields are composed of E and E contributions. Away from the ends the Faraday rule expression, equation (1), is rewritten as: 2E x A = −d /dt = −LdI/dt = −L X x A dI/dt. Given the fact that E is uniformly distributed, we have the more general expression, 2E x = −L X xdI/dt for any x.…”
Section: Discussionmentioning
confidence: 99%
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