2015
DOI: 10.1007/s00209-015-1565-x
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Pathologies of the Brauer–Manin obstruction

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Cited by 22 publications
(21 citation statements)
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References 22 publications
(38 reference statements)
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“…The fundamental reason is the Harpaz-Schlank theorem quoted above which implies that if HSP holds for X then the Brauer-Manin obstruction applied toétale covers is the only obstruction for the Hasse principle. Since now there are many counter-examples to this claim (see [28], [20] and [3]) we get that there are two-and three-dimensional counterexamples to HSP. However we can offer some positive results; see Theorems 13.3, 13.7 and 14.8 in the next two sections.…”
Section: The Homotopy Section Principlementioning
confidence: 88%
“…The fundamental reason is the Harpaz-Schlank theorem quoted above which implies that if HSP holds for X then the Brauer-Manin obstruction applied toétale covers is the only obstruction for the Hasse principle. Since now there are many counter-examples to this claim (see [28], [20] and [3]) we get that there are two-and three-dimensional counterexamples to HSP. However we can offer some positive results; see Theorems 13.3, 13.7 and 14.8 in the next two sections.…”
Section: The Homotopy Section Principlementioning
confidence: 88%
“…In §6 we give an example of a minimal conic bundle over an elliptic curve for which degrees do not capture the Brauer-Manin obstruction. This is unsurprising (and somewhat less disappointing) given the known pathologies of the Brauer-Manin obstruction on quadric fibrations [CTPS16]. In §6 we note that degrees do capture the Brauer-Manin obstruction on minimal rational conic bundles and on Severi-Brauer bundles over elliptic curves with finite Tate-Shafarevich group (See Theorem 6.1).…”
Section: Introductionmentioning
confidence: 95%
“…Hence X p is everywhere locally soluble. Furthermore assume p ≡ 1 (mod 8) to ensure that the invariant maps over Q 2 will carry out same as in the proof. Then X p will be a counterexample to the Hasse principle given by a 3-torsion Brauer class in the algebraic Brauer group.…”
Section: P =mentioning
confidence: 99%
“…This is a contradiction, so we may assume that y 2 and z 2 are both odd. Now we use formula (8) to compute the invariant. We get…”
Section: Proof Of (C)mentioning
confidence: 99%
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