“…Using Method 1, ( R )- 34 (1.27 g, 3.17 mmol), 4 M HCl (5.6 mL), Et 3 N (962 mg, 9.51 mmol), and AcCl (298 mg, 3.80 mmol) gave the desired compound ( R )- 3 as a white solid (981 mg, 90%): R f = 0.27 (20:1 CH 2 Cl 2 /MeOH); mp 147–148 °C; [α] D 24 –16.1° ( c 1.0, CHCl 3 ); 1 H NMR (CDCl 3 ) δ 2.03 (s, C H 3 C(O)), 3.39 (s, OC H 3 ), 3.46 (dd, J = 4.3, 9.3 Hz, C H H′OCH 3 ), 3.81 (dd, J = 4.3, 9.3 Hz, CH H ′OCH 3 ), 4.40–4.48 (m, NHC H 2 ), 4.58 (dt, J = 4.3, 7.0 Hz, C H CH 2 ), 6.49 (d, J = 7.0 Hz, N H ), 6.83–6.93 (m, 2 Ar H , N H ), 6.93–6.97 (m, Ar H ), 7.00 (d, J = 8.2 Hz, 2 Ar H ), 7.27 (d, J = 8.2 Hz, 2 Ar H ), 7.32 (m, 2 Ar H ), addition of excess ( R )-(−)-mandelic acid to a CDCl 3 solution of ( R )- 3 gave only one signal for the acetyl methyl and one signal for the methoxy protons; 13 C NMR (CDCl 3 ) δ 23.2 (C(O) C H 3 ), 43.0 (NH C H 2 ), 52.4 ( C HCH 2 ), 59.1 (O C H 3 ), 71.6 (CH C H 2 ), 118.9, 119.0, 123.3, 128.9, 132.7, 156.7 (Ar C ), 169.9, 170.3 (2 C (O)), the remaining two aromatic peaks were not detected and are believed to overlap with nearby signals; LRMS (ESI + ) 365.1 [M+Na] + (calcd for C 19 H 22 N 2 O 4 Na + 365.1); HRMS (ESI + ) 365.1478 [M+Na] + (calcd for C 19 H 22 N 2 O 4 Na + 365.1478); Anal. Calcd.…”