2018
DOI: 10.1007/s11071-018-4367-y
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On the nonlinear dynamical systems within the generalized fractional derivatives with Mittag–Leffler kernel

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Cited by 142 publications
(95 citation statements)
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“…3. for m = 3, if the discriminant of H (Λ), D(H ) is positive, then Routh-Hurwitz conditions are the necessary and sufficient conditions for (11) (11) is satisfied for all σ ∈ [0, 1). 6.…”
Section: Theoremmentioning
confidence: 99%
See 1 more Smart Citation
“…3. for m = 3, if the discriminant of H (Λ), D(H ) is positive, then Routh-Hurwitz conditions are the necessary and sufficient conditions for (11) (11) is satisfied for all σ ∈ [0, 1). 6.…”
Section: Theoremmentioning
confidence: 99%
“…Although [2][3][4][5][6] has completed a great deal of work on dynamic modeling of influenza, it is limited to ordinary differential equations. However, currently, it has been found that the use of fractional differential equations to model many different fields of phenomena has been very successful [7][8][9][10][11][12][13][14][15][16][17][18]. For instance, in mathematical epidemiology, Ebola virus epidemic has been modeled with fractional-order differential equations by [19].…”
Section: Introductionmentioning
confidence: 99%
“…These quantities are essentially defined by convolutions integrals with kernel of type power law functions that define the well-know Caputo, Riemann-Liouville and Riesz-Feller fractional operators, which are focus of recent mathematical applications [19][20][21][22][23][24][25][26]. Nowadays, a new family of kernels has been used to describe generalised diffusive models [27][28][29][30][31][32][33][34]. In this context, it is possible to define the generalised diffusion equation…”
Section: Introductionmentioning
confidence: 99%
“…Example of Equation(10) and error Equation(19), and in this is table, y is constant and t, x, n are variable with = 0.5, 3 = 0.6 3.44413849 × 10 −4 4.13886868 × 10 −6 3.83621593 × 10 −7 1 = 0.1, 2 = 0.5, 3 = 0.9 8.22822045 × 10 −4 4.20641342 × 10 −6 3.83627607 × 10 −7 1 = 0.3, 2 = 0.4, 3 = 0.8 4.69460091 × 10 −4 4.16779793 × 10 −6 3.83664363 × 10 −7 1 = 0.1, 2 = 0.2, 3 = 0.3 3.57606141 × 10 −4 1.26366819 × 10 −6 9.50441948 × 10 −7…”
mentioning
confidence: 99%
“…Example of Equation(10) and error Equation(19), and in this table, y is constant and t, x, n are variable with 1 , 2 = 0.2 7.33866827 × 10 −6 1.99765798 × 10 −6 3.76046720 × 10 −7 1 = 0.3, 2 = 0.6 4.24195754 × 10 −6 1.14902327 × 10 −6 2.18345928 × 10 −7 1 = 0.1, 2 = 0.6 5.06981634 × 10 −5 1.37448038 × 10 −6 2.59171862 × 10 −7 1 = 0.3, 2 = 0.4 5.06981634 × 10 −5 1.36667106 × 10 −6 2.55903570 × 10 −7 = 0.5, 3 = 0.6 2.53215157 × 10 −6 6.69354326 × 10 −7 1.279053657 × 10 −7 1 = 0.1, 2 = 0.5, 3 = 0.9 2.53215157 × 10 −6 5.69364388 × 10 −7 1.1932046303 × 10 −7 1 = 0.3, 2 = 0.4, 3 = 0.8 2.53215157 × 10 −6 5.01438508 × 10 −7 1.0589717284 × 10 −7 1 = 0.2, 2 = 0.6, 3 = 0.7 5.55083179 × 10 −6 1.03736449 × 10 −7 2.2208255269 × 10 −7…”
mentioning
confidence: 99%