2003
DOI: 10.4064/sm155-2-1
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On the Banach–Stone problem

Abstract: Abstract. Let X and Y be locally compact Hausdorff spaces, let E and F be Banach spaces, and let T be a linear isometry from C 0 (X, E) into C 0 (Y, F ). We provide three new answers to the Banach-Stone problem: (1) T can always be written as a generalized weighted composition operator if and only if F is strictly convex; (2) if T is onto then T can be written as a weighted composition operator in a weak sense; and (3) if T is onto and F does not contain a copy of ∞ 2 then T can be written as a weighted compos… Show more

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Cited by 18 publications
(14 citation statements)
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“…[ 12] PROOF. Given t e ch(N) and y* e N*(t) there exists s e ch(M) and x* e ext(X(s)*) such that T*(y* o \jr,) = x* o \j/ s .…”
Section: = \\H\\ = H(t) and The Functions G(-) = H(-)u //(•) = /I(-)mentioning
confidence: 99%
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“…[ 12] PROOF. Given t e ch(N) and y* e N*(t) there exists s e ch(M) and x* e ext(X(s)*) such that T*(y* o \jr,) = x* o \j/ s .…”
Section: = \\H\\ = H(t) and The Functions G(-) = H(-)u //(•) = /I(-)mentioning
confidence: 99%
“…Jeang and Wong [12] have observed that if E is real and not strictly convex, there exist norm-one elements u u u 2 in E such that Then the operator T from C({1, 2}, K) into C({1, 2}, E) by is an isometry. The next two examples show that the conclusion of Theorem 3.4 and Theorem 3.5 can fail if either the density of the linear span of N*(t) or the triviality of Z(E 2 (0) is not satisfied.…”
Section: Theorem 36 Suppose There Exists An Isometry Tfrom Cq(q E\mentioning
confidence: 99%
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“…After Jerison [23], many authors worked on different variants of the vector-valued Banach-Stone Theorem (see [12,16,18,20,[22][23][24]). In particular, as an extension of the representation theorem of Abramovich [1], Hernandez, Beckenstein and Narici proved in [12] that if T is an isometric biseparating linear map from C(X, E) onto C(Y, F) then T is a weighted composition operator Tf (y) -h{y)(f {<p{y))).…”
Section: Tf (Y) = H{y)(f (mentioning
confidence: 99%
“…It is easy to see that the map T : C(X, E) −→ C(Y, F ) defined, for each f ∈ C(X, E), by (T f )(x, i) := f (x), e i (where {e 1 , e 2 } is the canonical basis in K 2 ), and (T f )(p j ) := 0 for all j, is a linear isometry with codimension n 0 . As in [17], it can be checked that T is not a weighted composition map.…”
Section: Preliminaries and Main Resultsmentioning
confidence: 99%