2012
DOI: 10.1109/lcomm.2012.041112.112564
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Notes on "Exact Decoding Probability Under Random Linear Network Coding"

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Cited by 25 publications
(21 citation statements)
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“…Then, under the independence assumption, we can compute the cdf for broadcast with telescopic codes, e.g. (8) with the resulting pmf in (9). f TB (t; N, 1 , .…”
Section: Discussionmentioning
confidence: 99%
See 1 more Smart Citation
“…Then, under the independence assumption, we can compute the cdf for broadcast with telescopic codes, e.g. (8) with the resulting pmf in (9). f TB (t; N, 1 , .…”
Section: Discussionmentioning
confidence: 99%
“…Nevertheless, RLNC based techniques have the caveat of introducing overhead due to mainly two reasons in the coding process. First, retransmissions of linearly dependent packets occur due to the random selection of the coefficients [8], [9]. Second, in order to later perform decoding, the coding coefficients are appended to each coded packet before being sent through the network.…”
Section: Introductionmentioning
confidence: 99%
“…For RLNC, this is not the case, since the occurrence of linearly-dependent coded packets is small, because all coding coefficients are used. Even for GF(2), the average amount of redundant packets for RLNC has been proven to be 1.6 packets after g have been transmitted [41,42], but less than the cases where sparse codes are utilized. Overall, we observe that there is a trade-off between goodput and linearly-dependent coded packets' transmission overhead.…”
Section: Encodingmentioning
confidence: 99%
“…Typically, the exact decoding probability under RLNC is derived in a fixed topology [11][12][13][14] . Trullols-Cruces et al [11] computed the exact probability that a receiver obtains N linearly independent packets among K N ≥ received packets, when the senders use RLNC over a Galois field.…”
Section: Introductionmentioning
confidence: 99%
“…This problem is equivalent to computing the probability that a N K × matrix has rank N , where each element is randomly selected from a Galois field with equal probability. Deriving the probability that this matrix has full rank in Theorem 1 [12] can be viewed as a special case of Theorem 1 [14] .…”
Section: Introductionmentioning
confidence: 99%