2009
DOI: 10.1088/0253-6102/51/3/25
|View full text |Cite
|
Sign up to set email alerts
|

New Convenient Way for Deriving Exponential Operators' Disentangling Formulas and Their Applications (II)

Abstract: In the preceding paper [Commun. Theor. Phys. 51 (2009) 321] we have recommended a convenient method for disentangling exponential operators in the form of exp{B + C}, trying to find an operator A that satisfies [A, B] = C, and [A,[A,B]] = 0, then from the Baker–Hausdorff formula we have exp{B + C} = exp{B+[A, B]} = eA eB e−A. After arranging eA eB = eB eA eW, the disentangling exp{B + C} = eB eW is obtained. In this work we use this method to two-mode case, especially, derive the normal ordering fo… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1

Citation Types

0
2
0

Year Published

2009
2009
2016
2016

Publication Types

Select...
6

Relationship

1
5

Authors

Journals

citations
Cited by 9 publications
(2 citation statements)
references
References 14 publications
0
2
0
Order By: Relevance
“…( 5), this is equivalent to the disentangling It must be noted that the purpose of this disentangling is not for obtaining a nomal ordering, so this task is different from what we have done in Ref. [2]. We now do it without appealing to the SU(2) Lie algebra theory obeyed by ((a…”
Section: A Preliminary Formulamentioning
confidence: 98%
See 1 more Smart Citation
“…( 5), this is equivalent to the disentangling It must be noted that the purpose of this disentangling is not for obtaining a nomal ordering, so this task is different from what we have done in Ref. [2]. We now do it without appealing to the SU(2) Lie algebra theory obeyed by ((a…”
Section: A Preliminary Formulamentioning
confidence: 98%
“…Instead, in our preceding paper [1] we have recommended an alternate method for disentangling some exponential operators, it can be summarized as follows. For decomposing exp{B + C}, we try to find an operator A, which satisfies [A, B] = C, and [A, [A, B]] = 0, then from the Baker-Hausdorff formula [2] e A B e…”
Section: Introductionmentioning
confidence: 99%