1987
DOI: 10.1007/bf01240454
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Necessary and sufficient conditions for invertibility of nonautonomous functional-differential operators

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Cited by 25 publications
(11 citation statements)
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“…Therefore, according to Theorem 5, the operator L Q : l ∞ (Z, E) → l ∞ (Z, E) has a continuous inverse. Conversely, if the operator L Q : l ∞ (Z, E) → l ∞ (Z, E) has a continuous inverse, then, according to Theorem 5, for every number H > 0 there exists a number r > 0 and an element A = (A n ) n∈Z ∈ E 1 for which inequality (17) [and, hence, (18)] is also true. Inequality (18) yields (24).…”
Section: Theorem 5 For Every Number H > 0 There Exist a Number R > mentioning
confidence: 94%
See 1 more Smart Citation
“…Therefore, according to Theorem 5, the operator L Q : l ∞ (Z, E) → l ∞ (Z, E) has a continuous inverse. Conversely, if the operator L Q : l ∞ (Z, E) → l ∞ (Z, E) has a continuous inverse, then, according to Theorem 5, for every number H > 0 there exists a number r > 0 and an element A = (A n ) n∈Z ∈ E 1 for which inequality (17) [and, hence, (18)] is also true. Inequality (18) yields (24).…”
Section: Theorem 5 For Every Number H > 0 There Exist a Number R > mentioning
confidence: 94%
“…These operators were studied in [14][15][16][17][18][19][20]. The definition of c-continuous operator that uses locally convergent sequences was proposed by the author (see, e.g., [21,22]).…”
Section: Auxiliary Statementsmentioning
confidence: 99%
“…These operators were studied in [2][3][4][5][6][7][8][9], etc. The definition of c-continuous operator that uses locally convergent sequences was proposed by the author (see, e.g., [10][11][12]).…”
Section: Main Functional Spaces and C-continuous Operatorsmentioning
confidence: 99%
“…The function G.t / is called the Green function [15,21] of the operator L defined by relation (6). With the use of this function, for every h 2 C 0 .R; E/; the unique bounded solution of the equation…”
Section: Representation Of Bounded Solutions Of Linear Inhomogeneous mentioning
confidence: 99%
“…Следовательно, для H = 0 выполняется неравенство (10). Поэтому уравне-ние (45) имеет хотя бы одно решение x ∈ C 1 (R, E).…”
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