Investigation of bismuth-based perovskite system: (1−x)Bi(Ni2∕3Nb1∕3)O3–xPbTiO3

Abstract

High piezoelectric performance in a new Bi-based perovskite of (1−x)Bi(Ni1/2Hf1/2)O3−xPbTiO3

High electromechanical response in the non morphotropic phase boundary piezoelectric system PbTiO3−Bi(Zr1/2Ni1Pandey1, Narayan2, Khatua3 et al. 2018Phys. Rev. B282110View full textAdd to dashboardCite

“…Consequently, it can induce interesting changes in the crystal structure, ferroelectric and piezoelectric properties of PbTiO3 [11][12][13][14][15][16][17][18][19][20]. Examples include Bi(Ni1/2Ti1/2)O3-PbTiO3 (BNT-PT) [11], 3 3 Bi(Mg1/2Ti1/2)O3-PbTiO3 (BMT-PT) [12,17,19], Bi(Mg1/2Zr1/2)O3-PbTiO3 (BMZ-PT) [13,17,19], Bi(Zn1/2Ti1/2)O3-PbTiO3 (BZT-PT) [14,18,19], Bi(Zn1/2Zr1/2)O3-PbTiO3 (BZZ-PT) [14,19], Bi(Zn1/2Sn1/2)O3-PbTiO3 [14], Bi(Zn3/4W1/4)O3-PbTiO3 [15,18], Bi(Mg3/4W1/4)O3-PbTiO3 (BMW-PT) [16], Bi(Ni2/3Nb1/3)O3-PbTiO3 [20] etc. From the structural standpoint, depending on how they influence the tetragonality (c/a = 1.06) of PbTiO3, the different PT-BM M systems can be categorized in three groups: (i) those which increase the tetragonality such as Bi(Zn1/2Ti1/2)O3 and Bi(Zn3/4W1/4)O3 [14,15], (ii) do not affect the tetragonality such as Bi(Zn1/2Zr1/2)O3 and Bi(Zn1/2Sn1/2)O3 [14], and (iii) the majority which decrease the tetragonality of PbTiO3.…”

Structure and piezoelectric characteristics of (0.90-x)BiScO3-xPbTiO3-0.10Pb(Mn1/3Ta2/3)O3 system

“…The magnitude of Qm increased significantly, comparable to the unmodified BS-PT (~200) 16) and BNNPT65 system (70-140). 18) Analyzed from dielectric spectra in Fig. 2, the dielectric constant and loss at x = 0.60 come to the lowest value at 924.9 and 0.012, respectively.…”

Relaxor-normal ferroelectric phase transition and significantly enhanced electromechanical strain behavior in Bi(Ni1/2Ti1/2)O3–PbTiO3–Pb(Mg1/3Nb2/3)O3 ternary system close to the morphotropic phase boundary

“…Generally speaking, the dielectric behavior of (0.65 − x)BNT-0.35PT-xPMN ceramics changed drastically with substituting PMN for BNT. It is obvious that 0.65BNT-0.35PT samples (x = 0) have higher conductivity as indicated by their dielectric loss values and dielectric peak values, probably owing to the valence variation of Ni cations (Ni 2+ /Ni 3+ ) during sintering [34]. However, this can be obviously improved by the substitution of PMN for BNT.…”