“…It is easy to see that ((q, j), The following example shows that the statement of Theorem 3.5 is not true if we allow the rows of A to be non-consecutive. If Theorem 3.5 would be valid also in the case that the rows to be checked for linear independence are non-consecutive, e.g., the first and the third row of A, we could apply Procedure 3.1 toÃ[1, 3|1, 2, 3, 4] which would result in a sequence γ containing only the pair (3,4). By Theorem 3.5 it would follow that both rows are linearly dependent, whereas the application of Procedure 3.1 to A[1, 3|1, 2, 3, 4] which is identical with the last two rows ofà gives the correct result.…”