2018
DOI: 10.1063/1.5020271
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Humidity effects on surface dielectric barrier discharge for gaseous naphthalene decomposition

Abstract: Experiments are performed using dry and humid air to clarify the effects of water vapour on the characteristics of surface dielectric barrier discharge (SDBD) and investigate its impact on the performance of the SDBD for decomposition of gaseous naphthalene in air stream. The current characteristics, including the discharge and the capacitive currents, are deeply analyzed and the discharge mechanism is explored. The results confirmed that the humidity affected the microdischarge distribution without affecting … Show more

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Cited by 32 publications
(21 citation statements)
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“…The same setup was used for the gas‐phase decomposition of naphthalene in dry and humid air. The decomposition efficiency again strongly depended on the applied voltage and was derived to be around 90 % for 6 kV and a relative humidity between 0 % and 60 % .…”
Section: Dielectric Barrier Dischargesmentioning
confidence: 99%
“…The same setup was used for the gas‐phase decomposition of naphthalene in dry and humid air. The decomposition efficiency again strongly depended on the applied voltage and was derived to be around 90 % for 6 kV and a relative humidity between 0 % and 60 % .…”
Section: Dielectric Barrier Dischargesmentioning
confidence: 99%
“…However, RH levels were significantly ( P < 0.05) increased after the ACP treatment using 100% N 2 and 80% N 2 + 20% O 2 for both treatment times (Table 2), which might be due to a minor leak in the ACP‐treatment chamber. In short, the increase of reactive species concentrations observed in this study was due to the presence of oxygen molecules, energy density generated by ACP, and the contribution of RH (Abdelaziz et al., 2018; Abdelaziz et al., 2019; Mastanaiah et al., 2013; Osawa et al., 2017).…”
Section: Resultsmentioning
confidence: 65%
“…Here, the radicals H˙ and OH˙ are generated through the electron impact dissociation and excitation reaction of H 2 O molecules as shown in R(15)–R(18). 3,43 H 2 O + e → OH˙ + H˙ + ee + O 2 → e + O( 1 D) + O( 3 P)O( 1 D) + H 2 O → 2OH˙…”
Section: Resultsmentioning
confidence: 99%