1992
DOI: 10.1103/physrevc.46.1546
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How well do we know theE2/M1 ratio for the Δ(1232)?

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Cited by 8 publications
(3 citation statements)
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“…In both models, N(940) is dominated by the three-quark state in the lowest energy. This is also the case for ∆(1232), and the d-wave excitation of quarks is hardly found in this state [26,27,28]. We note that N(940) and ∆(1232) in the CPA model have the three-quark component with (j q , t q ) = (3/2, 3/2) and (j q , t q ) = (1/2, 1/2), respectively.…”
Section: B Mixings Coefficientsmentioning
confidence: 92%
“…In both models, N(940) is dominated by the three-quark state in the lowest energy. This is also the case for ∆(1232), and the d-wave excitation of quarks is hardly found in this state [26,27,28]. We note that N(940) and ∆(1232) in the CPA model have the three-quark component with (j q , t q ) = (3/2, 3/2) and (j q , t q ) = (1/2, 1/2), respectively.…”
Section: B Mixings Coefficientsmentioning
confidence: 92%
“…1+ at the resonance energy. Both the RPI [5] and VPI [7] groups have found ratios near −1.5% in the past. However, while the PDG [8] quotes these values, a number of recent determinations have found larger negative values.…”
Section: The E2/m1 Ratiomentioning
confidence: 99%
“…By weighting data, we magnify changes in the multipole amplitudes, and more clearly see where data conflicts occur. In the case of the E2/M1 ratio, for example, an early forced fit [9] to Σ data resulted in a value of −2.9%, when the predominant value was −1.5%.…”
mentioning
confidence: 99%