“…If γ 4 (G) ∼ = C 3 , then as in [3] by using [2], there exist x, y ∈ G such that a = (x, y), b = (x, y, y), c = (x, y, y, y), G ′ = a, b, c , γ 3 (G) = b, c and γ 4 (G) = c . Therefore by Lemmas 2.1 and 2.2, (a−1) 2 (b−1) 2 (c −1) 2 ∈ KG [13] = 0, a contradiction. Proof.…”