2017
DOI: 10.1080/00927872.2017.1339059
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On Lie nilpotent modular group algebras

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Cited by 7 publications
(9 citation statements)
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“…Thus γ 6 (G) = 1 and γ 3 (G) is an abelian group. Also |G ′ | ≥ 3 3 and the exponent of γ 3 (G) is at most 3, as for a 1 , a 2 , a 3 ∈ G, ((a 1 , a 2 , a 3 ) −1) 8 ∈ (KG [3] ) 8 ⊆ KG [14] . By Lemma 2.3, (3 m i − 1) is an even number and γ 3 (G)G ′3 /G ′3 = 3 r .…”
Section: Resultsmentioning
confidence: 99%
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“…Thus γ 6 (G) = 1 and γ 3 (G) is an abelian group. Also |G ′ | ≥ 3 3 and the exponent of γ 3 (G) is at most 3, as for a 1 , a 2 , a 3 ∈ G, ((a 1 , a 2 , a 3 ) −1) 8 ∈ (KG [3] ) 8 ⊆ KG [14] . By Lemma 2.3, (3 m i − 1) is an even number and γ 3 (G)G ′3 /G ′3 = 3 r .…”
Section: Resultsmentioning
confidence: 99%
“…Let m 2 = 2, m 3 = 1. Then by [3], there exist x, y, z ∈ G such that b 1 = (x, y), b 2 = (x, z), c 1 = (x, y, y), G ′ = b 1 , b 2 , c 1 , d 1 , γ 3 (G) = c 1 and γ 4 (G) = d 1 Therefore by Lemma 2.1, (b 1 − 1) 2 (b 2 − 1) 2 (c 1 − 1) 2 (d 1 − 1) 2 ∈ KG[14] = 0, a contradiction. Suppose m 2 = m 3 = 1, then as in Lemma 2.5, G ′ is abelian and |G ′ | = 3 3 .…”
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confidence: 91%
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