2016
DOI: 10.1214/15-aap1127
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From transience to recurrence with Poisson tree frogs

Abstract: Consider the following interacting particle system on the $d$-ary tree, known as the frog model: Initially, one particle is awake at the root and i.i.d. Poisson many particles are sleeping at every other vertex. Particles that are awake perform simple random walks, awakening any sleeping particles they encounter. We prove that there is a phase transition between transience and recurrence as the initial density of particles increases, and we give the order of the transition up to a logarithmic factor.Comment: P… Show more

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Cited by 42 publications
(79 citation statements)
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“…On the other hand, the frog model on the infinite d-ary tree can be either transient a.s. or recurrent a.s., depending on the initial configuration. For example, on the d-ary tree when (η(v)) v is i.i.d.-Poisson(µ), the frog model is recurrent or transient depending on whether µ is greater or less than a critical value µ c (d) [5,7]. In [8], the authors give a theorem comparing frog models with different initial conditions on the same graph, which shows that the frog model on the d-ary tree is recurrent if η(v) pgf Poisson(µ) for all v for some µ > µ c (d).…”
Section: Introductionmentioning
confidence: 99%
“…On the other hand, the frog model on the infinite d-ary tree can be either transient a.s. or recurrent a.s., depending on the initial configuration. For example, on the d-ary tree when (η(v)) v is i.i.d.-Poisson(µ), the frog model is recurrent or transient depending on whether µ is greater or less than a critical value µ c (d) [5,7]. In [8], the authors give a theorem comparing frog models with different initial conditions on the same graph, which shows that the frog model on the d-ary tree is recurrent if η(v) pgf Poisson(µ) for all v for some µ > µ c (d).…”
Section: Introductionmentioning
confidence: 99%
“…We study two problems presented to us by I. Benjamini [8] (see also [20,Open Question 5]). In these two problems we seek an estimate which holds uniformly in the identity of the origin o. Deterministically, CT(T d,n ) ≥ n. Conversely, CT(T d,n ) can be bounded from above by the cover time of T d,n by a single SRW, which Aldous [1] showed is ≍ n 2 d n log d. To the best of the author's knowledge, the best previously known upper bound on CT(T d,n ) is exponential in n, i.e.…”
Section: Introduction and Resultsmentioning
confidence: 99%
“…Next we compute E[x V ; D i ] for each i beginning with i = 1. represents having all frogs that go to a from the sub-tree rooted at b then travel to the root; and D (2) 2 represents having at least one frog that travels to a from the sub-tree rooted at b then go to b ′ (i.e. D 2 /D…”
Section: Constructing the Operatormentioning
confidence: 99%