1995
DOI: 10.1090/surv/042
|View full text |Cite
|
Sign up to set email alerts
|

Free Lattices

Abstract: If x, y and z are elements of a lattice, then x ∨ (y ∨ (x ∧ z)) = x ∨ y is always true, while x ∨ y = z is usually not true. Is there an algorithm that, given two lattice expressions p and q, determines whether p = q holds for every substitution of the variables in every lattice? The answer is yes, and finding this algorithm (Corollary to Theorem 6.2) is our original motivation for studying free lattices. We say that a lattice L is generated by a set X ⊆ L if no proper sublattice of L contains X. In terms of t… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

2
309
0

Year Published

2001
2001
2006
2006

Publication Types

Select...
6
2

Relationship

1
7

Authors

Journals

citations
Cited by 195 publications
(311 citation statements)
references
References 11 publications
(16 reference statements)
2
309
0
Order By: Relevance
“…For example the lattices associated with (x ∨ (y ∧ z)) ∧ (y ∨ z) and with (x ∨ (y ∧ z)) ∧ (y ∨ (x ∧ z)) are diagrammed in Figure 5. (Since the second lattice is semidistributive but the first is not, (x ∨ (y ∧ z)) ∧ (y ∨ z) has a lower cover but (x ∨ (y ∧ z)) ∧ (y ∨ (x ∧ z)) does not; see [10]). …”
Section: Automatic Drawingmentioning
confidence: 99%
See 1 more Smart Citation
“…For example the lattices associated with (x ∨ (y ∧ z)) ∧ (y ∨ z) and with (x ∨ (y ∧ z)) ∧ (y ∨ (x ∧ z)) are diagrammed in Figure 5. (Since the second lattice is semidistributive but the first is not, (x ∨ (y ∧ z)) ∧ (y ∨ z) has a lower cover but (x ∨ (y ∧ z)) ∧ (y ∨ (x ∧ z)) does not; see [10]). …”
Section: Automatic Drawingmentioning
confidence: 99%
“…The usual algorithm to find a linear extension of P (graph theorists call this topological sorting) can be easily modified to calculate this rank function in linear time. (See Chapter 11 of [10] for a discussion of algorithms for ordered sets and lattices. )…”
Section: The Rank Functionmentioning
confidence: 99%
“…There may not be a b so that (a, b) is critical. Although it is phrased differently, [12,Theorem 2.56] states that the meet semi-distributive property of a lattice is equivalent to the property that for any join-irreducible a there is a unique b so that (a, b) is subcritical. The dual result also holds.…”
Section: By Theorem 6 S(y ∨ Z) = S(y ) ∪ S(z)mentioning
confidence: 99%
“…We recall the representation of congruence relations on a finite lattice in terms of the dependency relation; see, e.g., [4], pages 40-41.…”
Section: There Is a Lattice Embeddingmentioning
confidence: 99%