“…At pH 7 and 8, a second poorly resolved wave is seen at E p = +1.40 V. Considering the molecular structure, it is reasonable to assume that the main oxidation peak observed could only be ascribed to the unique function present in the molecule susceptible to be oxidized, the oxygen aromatic ether. Previous work on similar alkoxybenzenes and literature data indicated that the oxidation process proceeds at the aromatic nucleus, through a one-electron transfer, via the formation of an unstable cation-radical intermediate that could undergo further subsequent reactions. − The second poorly resolved wave observed at pH 7 and 8, not detected for fluoxetine, must then be related to the oxidation of the species resulting from the formation and dimerization of the initial cation radical (Scheme ). , As this moiety is present in fluoxetine (Scheme ), it seems reasonable to infer that the pharmaceutical drug shares the same oxidation pattern. Moreover, the results observed for this analogue, and in particular the evidence of the formation of dimeric species, could contribute to explain the strong adsorption processes that occur when using glassy carbon electrodes for measuring fluoxetine, which is perhaps the main reason for the limited use of electrochemical methods for its quantification. , …”