“…If the Reeb vector field ξ is tangent to 𝑘𝑒𝑟π * , then 𝐷 0 ∩ 𝑘𝑒𝑟𝑄 = 𝑠𝑝𝑎𝑛{ξ}. Consider a pair of almost complex structures {𝐽 1 , 𝐽 2 } on 𝑅12 as in the following:𝐽 1 (∂ 1 , … ∂ 12 ) = (− ∂ 3 , − ∂ 4 , ∂ 1 , ∂ 2 , − ∂ 7 , − ∂ 8 , ∂ 5 , ∂ 6 , − ∂ 11 , − ∂ 12 , ∂ 9 , ∂ 10 ), 𝐽 2 (∂ 1 , … , ∂ 12 ) = (− ∂ 2 , ∂ 1 , ∂ 4 , − ∂ 3 , − ∂ 6 , ∂ 5 , ∂ 8 , − ∂ 7 , − ∂ 10 , ∂ 9 , ∂ 12 , − ∂ 11 )Define a map π: 𝑅 𝟙𝟛 → 𝑅 𝟞 such that π(𝑥 1 , … , 𝑥 13 ) = (𝑥 2 , 𝑥 3 , 𝑥 6 , 𝑥 8 , 𝑥 9 , 𝑥 12 ).…”