2010
DOI: 10.1007/978-0-8176-4888-6_8
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Concentration of the Integral Norm of Idempotents

Abstract: This is a companion paper of a recent one, entitled Integral concentration of idempotent trigonometric polynomials with gaps. New results of the present work concern L 1 concentration, while the above mentioned paper deals with L p -concentration.Our aim here is two-fold. At the first place we try to explain methods and results, and give further straightforward corollaries. On the other hand, we push forward the methods to obtain a better constant for the possible concentration (in L 1 norm) of an idempotent o… Show more

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Cited by 3 publications
(18 citation statements)
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“…But in a sense this is due to a "cheating" in the extent that we can simulate powers of Dirichlet kernels by products of their scaled versions. In a forthcoming note [10] we show, however, that on the finite groups Z/qZ uniform in q L 1 concentration does really fail.…”
Section: Remark 14mentioning
confidence: 80%
“…But in a sense this is due to a "cheating" in the extent that we can simulate powers of Dirichlet kernels by products of their scaled versions. In a forthcoming note [10] we show, however, that on the finite groups Z/qZ uniform in q L 1 concentration does really fail.…”
Section: Remark 14mentioning
confidence: 80%
“…Now if ρ ≤ k + 1, we also have 0 ≤ τ ≤ k + 1, so the number τ of choosing e 1 s is exactly λ, the mod k + 2 reduced residue of ν, and consequently σ = (ν − λ)/(k + 2) = µ. That results in formula (4) for a ± (ν), while (5) follows by Parseval's formula. Whence the assertion is proved.…”
Section: Notations and A Few General Formula For The Numerical Analysismentioning
confidence: 92%
“…As the error is at most δ, it suffices to show that p(t) := P 10 (t) + δ < 0 in [3,4]. Now From the explicit formula of p(t) we consecutively compute also p ′′ (3) = −23.12291565 < 0, p ′′′ (3) = −93.80789264 < 0 and p (4) (3) = −324.0046433, p (5) (3) = −978.7532737..., p (6) (3) = −3144.062078..., p (7) (3) = −5587.909055..., all < 0. Thus p (j) (3) < 0 for j = 0, .…”
Section: Consequently We Havementioning
confidence: 99%
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