“…From the results of the first phase, a basic candidate solution set I b ={3,5,7,8} is obtained from the candidate loop body by reselectable instruction map table. The basic candidate solutions generate a set of solution space {φ, 3, 5, 7, 8, (3,5), (3,7), (3,8), (5,7), (5,8), (7,8), (3,5,7), (3,5,8), (3,7,8), (5,7,8), (3,5,7,8)}. But, the branch and bound procedure discards the element 3 and 8 by heuristically chosen lower bound ,which we used 0.5, because those elements does not contribute an optimum solution.…”