Abstract:3‐Acetylthiophen (I), polymerer Formaldehyd (II) und Norephedrin (III) kondensieren zu der Mannich‐ Base (IV), die mit dem 3‐Lithiothiophen (V) umgesetzt das Carbinol (VI) liefert.
“…From entry 1 to 4 it is understood that obtained 4a is impure and had low enantiomeric excess when literature method was followed. [24][25][26] In the case of entry 1 and 2, multiple recrystallizations from ethanol gave compound 4a with 100% ee but yield was drastically reduced to about 40%. By reducing the concentration of hydrochloric acid or temperature (entry 5 & 6) resulted in an incompletion of reaction.…”
Section: Scheme 1 Epimerization Of Ephedrinementioning
“…From entry 1 to 4 it is understood that obtained 4a is impure and had low enantiomeric excess when literature method was followed. [24][25][26] In the case of entry 1 and 2, multiple recrystallizations from ethanol gave compound 4a with 100% ee but yield was drastically reduced to about 40%. By reducing the concentration of hydrochloric acid or temperature (entry 5 & 6) resulted in an incompletion of reaction.…”
Section: Scheme 1 Epimerization Of Ephedrinementioning
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