[Ca(XeF2) ](AsF6)2: (n=4, 2.5): the first coordination compounds of Ca2+ with XeF2 ligand

The First Compound Containing a Metal Center in a Homoleptic Environment of XeF2 Molecules

“…[2,3] Metal centers in all the compounds of this type are coordinated simultaneously by XeF 2 molecules and [AF 6 ] À ions (A = As, Sb, P). The important feature of the compound described herein, Ca 2 (XeF 2 ) 9 (AsF 6 ) 4 , is that for the first time one calcium center is coordinated to XeF 2 molecules only (a homoleptic center) while the second is coordinated to XeF 2 molecules and [AsF 6 ] À ions.…”

“…The important feature of the compound described herein, Ca 2 (XeF 2 ) 9 (AsF 6 ) 4 , is that for the first time one calcium center is coordinated to XeF 2 molecules only (a homoleptic center) while the second is coordinated to XeF 2 molecules and [AsF 6 ] À ions. The reaction between Ca(AsF 6 ) 2 and XeF 2 , in anhydrous HF (aHF) as a solvent, yields two compounds: [Ca(XeF 2 ) n ]-(AsF 6 ) 2 ; n = 4 and 2.5. [2] Which compound is formed depends on the mole ratio of the reactants (n corresponds the mole ratio between XeF 2 and Ca).…”

“…The reaction between Ca(AsF 6 ) 2 and XeF 2 , in anhydrous HF (aHF) as a solvent, yields two compounds: [Ca(XeF 2 ) n ]-(AsF 6 ) 2 ; n = 4 and 2.5. [2] Which compound is formed depends on the mole ratio of the reactants (n corresponds the mole ratio between XeF 2 and Ca). Noted that an excess of XeF 2 is necessary (n > 4) in order to obtain pure [Ca(XeF 2 ) 4 ](AsF 6 ) 2 , free of [Ca(XeF 2 ) 2.5 ](AsF 6 ) 2 .…”

“…[2] Which compound is formed depends on the mole ratio of the reactants (n corresponds the mole ratio between XeF 2 and Ca). Noted that an excess of XeF 2 is necessary (n > 4) in order to obtain pure [Ca(XeF 2 ) 4 ](AsF 6 ) 2 , free of [Ca(XeF 2 ) 2.5 ](AsF 6 ) 2 . We believe that at lower concentrations of XeF 2 (n < 4), there is always also some HF coordinated to the Ca 2+ ion, this being lost as the solvent is removed.…”

The First Compound Containing a Metal Center in a Homoleptic Environment of XeF2 Molecules

“…The reaction between Ca(AsF 6 ) 2 and XeF 2 , in anhydrous HF (aHF) as a solvent, yields two compounds: [Ca(XeF 2 ) n ]-(AsF 6 ) 2 ; n = 4 and 2.5. [2] Which compound is formed depends on the mole ratio of the reactants (n corresponds the mole ratio between XeF 2 and Ca).…”