2010
DOI: 10.1016/j.dam.2009.11.006
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Bounds for short covering codes and reactive tabu search

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Cited by 9 publications
(7 citation statements)
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“…Vários resultados da função clássica foram transladados naturalmente para esse novo problema, e em [8], Mendes e outros provaram um resultado de coberturas (clássicas) via coberturas curtas. Foi provado c 5 (10, 7) = 2 e, a partir desse resultado, pôde-se concluir que K 5 (10, 7) = 9.…”
Section: Uma Variante: Coberturas Curtasunclassified
“…Vários resultados da função clássica foram transladados naturalmente para esse novo problema, e em [8], Mendes e outros provaram um resultado de coberturas (clássicas) via coberturas curtas. Foi provado c 5 (10, 7) = 2 e, a partir desse resultado, pôde-se concluir que K 5 (10, 7) = 9.…”
Section: Uma Variante: Coberturas Curtasunclassified
“…Indeed, short coverings might provide us with a way to store nonlinear codes using less memory than the classical ones. Their results might reach record-breaking on the classical codes, as obtained in [11]. On the theoretical viewpoint, results on short covering have been investigated in connection with additive combinatorics, graph theory, and group theory.…”
Section: Introductionmentioning
confidence: 99%
“…The number 2 is a generator of Z * 13 . By Theorem 4.4, the set X = (1, 2 2·2 , 2 2·1 ), (1, 2 2·1 , 2 2·2 ), (1, 2 2·5 , 2 2·3 ), (1, 2 2·3 , 2 2·5 ) = { (1,3,4), (1,4,3), (1,10,12), (1,12,10)} is a short covering of 2 · 12 = 24 elements of E. Since |E| = 30, we need to cover 6 remaining vectors of E. By Fact 1 of Lemma 5.5, these six vectors are: (1, 2, 11), (1,5,8), (1,6,7), (1,7,6), (1,8,5), (1,11,2). They are covered by (1,2 2·4 , −2 2·4 ) = (1, 9, 4).…”
Section: Upper Bound For Short Coveringsmentioning
confidence: 99%
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