Antimony Homologues of Dinitrogen and Azobenzene as Complex Ligands: Preparation and Structure of [SbSb{W(CO)₅}₃] and [PhSbSbPh{W(CO)₅}₃]

Abstract

d) S. Ofner, V. Rasetti, B. Zehnder, A. Eschenmoser, Helu. Chim. Acta 64 (1981) 1431. 161 A B,C,D-hexadehydrocorrinate is formed as by-product (fa. 4%) in the anaerobic cyclization of a secoporphyrinogen to nickel( 11)-C,D-tetradehydrocorrinates [2c].

Synthesis and structural characterisation of a novel 2,3-distibene-1,4-dione complex, [Pt(PEt3)2{η2-ButC(O)SbSbC(O)But}]

“…[Fe(CO) 4 {h 2 -[(SiMe 3 ) 2 CHSb] 2 }] 2 4 and [{W(CO) 5 } 3 (h 2 -, h 1 -,h 1 -RSbNSbR)] R = Ph, 5 Bu t ; 6 none of which contain functionalised distibene substituents. Our interest in low coordination antimony chemistry has recently led to us reporting the first example of a 2-stiba-1,3-dionatolithium complex 3 (E = Sb), 7 which we have begun to investigate as a possible transfer reagent in the formation of transition metal-stibadionate complexes (cf.…”

The role of the substituents in the chemistry of organoantimony(I) compounds

“…In contrast to the well characterized six membered rings, the structures of the polymeric forms of phenyl antimony are unknown. Coordination compounds with phenylantimony(I) ligands include the distibene complex [(PhSb) 2 {W(CO) 5 } 3 ], 63 and a monomeric phenylantimony(phenylstibinidene) moiety stabilized as carbene complex. 64 The structure of the latter is shown in Figure 1.…”

Transfer of polyantimony units

“…trapped in a solid neon matrix, 9 grey antimony, Zintl ions, 10 organo-substituted Sb precursors 11 and quite simply SbCl 3 (ref. [12][13][14] and its derivatives were used as starting materials. In the 1970s, the rst Sb n ligand complex [{Co(CO) 3 } 4 (m 3 -Sb) 4 ] was published by Dahl et al by the reaction of Co(OAc) 2 $H 2 O with SbCl 3 as antimony source (I, Fig.…”

“…1 ). 12 Even in the case of the complexes [Sb 2 {W(CO) 5 } 3 ] 13 ( II ) and [{LGa(NMe 2 )} 2 (μ,η 1:1 -Sb 4 )] 14 ( III ), SbCl 3 and Sb(NMe 2 ) 3 are used as precursors ( Fig. 1 , L = HC[C(Me)N(2,6-C 6 H 3 i Pr 2 )] 2 ).…”