“…Referring to Figure 2, assume that we are in state (1, 1, 0), and we move to state (1, 0, 1) by changing both B and C. If the delays in the circuit are slightly greater for input C, the circuit will momentarily be in state (1, 0, 0), and the output will go to 0 (a dynamic hazard). We could try to alter the circuit delays to make sure that the circuit goes through state (1,1,1) instead, but what if this state had also been set to 0 in the original Karnaugh map? In this case, no intermediate state will maintain the correct output, and an unavoidable hazard is present.…”