“…, x n ] be homogeneous of degree d, and suppose that n ≥ 2d and p > 1 2 (3d 4 − 4d 3 + 5d 2 ). An inspection of the proof of [11,Theorem 3.1] reveals that the conclusion of Theorem 2 follows at once whenever f * fails to be absolutely irreducible, even in the absence of the hypothesis on p. Henceforth, therefore, we may suppose that f * is absolutely irreducible. Given our hypothesis on p, we may apply Lemma 5(i) to f * with δ = d to deduce that a slice ξ ∈ F 3n+1 p exists for which f * | ξ is absolutely irreducible.…”