2010
DOI: 10.1007/s11225-010-9293-z
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A Sequent Calculus for a Negative Free Logic

Abstract: This article presents a sequent calculus for a negative free logic with identity, called N. The main theorem (in part 1) is the admissibility of the Cut-rule. The second part of this essay is devoted to proofs of soundness, compactness and completeness of N relative to a standard semantics for negative free logic.

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Cited by 9 publications
(10 citation statements)
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“…In formulating the rules for the free logics discussed here we take as our starting point the sequent calculus for the negative variety first introduced in [6]. We then streamline it by transforming it into a G3-style calculus along the lines of [19], and to a lesser extent, [16,20].…”
Section: The Formal Systems G3 Pf and G3 Nfmentioning
confidence: 99%
See 3 more Smart Citations
“…In formulating the rules for the free logics discussed here we take as our starting point the sequent calculus for the negative variety first introduced in [6]. We then streamline it by transforming it into a G3-style calculus along the lines of [19], and to a lesser extent, [16,20].…”
Section: The Formal Systems G3 Pf and G3 Nfmentioning
confidence: 99%
“…The language L utilized in this paper is a standard first order language without functions, adapted from [6], with the vocabulary defined as A formula of our language L is defined as…”
Section: Language Of Free Logicsmentioning
confidence: 99%
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“…where α is globally replaced in that sequent by another term β in the category A. 10 In first order classical predicate logic, function terms are not deductively general singular terms, but primitive names are. If we consider the conseqence relation of Peano Arithmetic, defined by setting P A iff P A, over the language of predicate logic with 0, successor, addition, multiplication and identity, where P A is an axiomatization of Peano Arithmetic, then the constant term 0 is not deductively general, since we have (∃x)(0 = x ) P A (that is, it's inconsistent with the axioms of P A for 0 be the successor of some number), but we do not have (∃x)(0 = x ) P A .…”
Section: A [K]mentioning
confidence: 99%