2020
DOI: 10.3390/w12113018
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A Century of Riverbank Protection and River Training in Bangladesh

Abstract: Protecting against riverbank erosion along the world’s largest rivers is challenging. The Bangladesh Delta, bisected by the Brahmaputra River (also called the Jamuna River), is rife with complexity. Here, an emerging middle-income country with the world’s highest population density coexists with the world’s most unpredictable and largest braided, sand-bed river. Bangladesh has struggled over decades to protect against the onslaught of a continuously widening river corridor. Many of the principles implemented s… Show more

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Cited by 17 publications
(20 citation statements)
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References 10 publications
(23 reference statements)
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“…These guide banks or Bell's bunds are longitudinal guiding structures that consist of an upstream curved head, a straight shank, and a downstream curved head [6,8,12,13]. Oberhagemann [3] describes in detail the subsequent developments in training the Ganges, Brahmaputra-Jamuna and Padma rivers over the last century. Van der Wal [1] complements this with additional historical information.…”
Section: Historymentioning
confidence: 99%
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“…These guide banks or Bell's bunds are longitudinal guiding structures that consist of an upstream curved head, a straight shank, and a downstream curved head [6,8,12,13]. Oberhagemann [3] describes in detail the subsequent developments in training the Ganges, Brahmaputra-Jamuna and Padma rivers over the last century. Van der Wal [1] complements this with additional historical information.…”
Section: Historymentioning
confidence: 99%
“…Integration over the cross-section gives the total sediment load Q s = Bq s . Substitution of the relation for u 3 gives Q s = B 1−b/3 mC 2b/3 Q b/3 i b/3 . As morphological equilibrium implies that the sediment load in the narrowed reach must be equal to the sediment load in the original unmodified reach, the ratio of new slope, i 1 , to original slope, i 0 , can then be related to the ratio of new width, B 1 , to original width, B 0 , by i 1 /i 0 = (B 1 /B 0 ) 1−3/b [7] (Figure 5/2.28 in [7]).…”
Section: Fundamentalsmentioning
confidence: 99%
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