1995
DOI: 10.1006/jctb.1995.1043
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11/30 (Finding Large Independent Sets in Connected Triangle-Free 3-Regular Graphs)

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Cited by 22 publications
(29 citation statements)
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“…We now present some elementary facts about difficult graphs. Part (iv) implies (v), for the following reason: Let v 1 , v 2 , v 3 , v 4 and v 5 be the five vertices of degree two in D, and suppose that a big set disjoint from {v 1 , v 2 } is desired. The graph D cannot contain the edges v 3 v 4 , v 3 v 5 , and v 4 v 5 , since it is triangle-free.…”
Section: Difficult Graphs and Link Graphsmentioning
confidence: 97%
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“…We now present some elementary facts about difficult graphs. Part (iv) implies (v), for the following reason: Let v 1 , v 2 , v 3 , v 4 and v 5 be the five vertices of degree two in D, and suppose that a big set disjoint from {v 1 , v 2 } is desired. The graph D cannot contain the edges v 3 v 4 , v 3 v 5 , and v 4 v 5 , since it is triangle-free.…”
Section: Difficult Graphs and Link Graphsmentioning
confidence: 97%
“…The graph D cannot contain the edges v 3 v 4 , v 3 v 5 , and v 4 v 5 , since it is triangle-free. Hence, two of the vertices among v 3 , v 4 and v 5 are nonadjacent. If v 3 and v 4 are nonadjacent, then there is a big set I whose only vertices of degree two are v 3 and v 4 ; this big set does not contain v 1 or v 2 , as desired.…”
Section: Difficult Graphs and Link Graphsmentioning
confidence: 97%
See 1 more Smart Citation
“…also [7]). (Note that there are exactly two connected graphs for which this bound is best-possible [2,3,5,8] and that Fraughnaugh and Locke [4] proved that every cubic triangle-free graph G has an independent set of cardinality at least 11 30 n(G)− 2 15 , which implies that, asymptotically, 5 14 is not the correct fraction.) In order to formulate the result of Heckman and Thomas and our extension of it we need some definitions.…”
mentioning
confidence: 96%
“…There were only two triangle-free 3-regular connected graphs known to have independence ratio 5 14 , although Locke [13] provided an infinite family of triangle-free 3-regular connected graphs with independence ratio approaching 11 30 . Fraughnaugh and Locke [8] proved that =(G ) 7&(G )&15:(G)&4 for every connected triangle-free graph G with maximum degree 3 and provided a polynomial-time algorithm which produces an independent set I such that =(G) 7&(G)&15 |I| &4, thereby proving that the lower bound for the independence ratio for graphs in this class approaches 11 30 . In this paper, we show that =(G ) 9&(G)&26:(G)&4 for every connected K 4 -free graph with maximum degree 4.…”
mentioning
confidence: 97%