The rank and symmetric rank of a symmetric tensor may differ.We work with three-dimensional tensors with complex entries. The entries of such a tensor are indexed by triples (i, j, k) in the Cartesian product of finite indexing sets I, J, K.and symmetric if I = J = K and the value of T (i|j|k) does not change under permutations of (i, j, k). The rank of T is the smallest r for which T can be written as a sum of r simple tensors, and such a representation is called a rank decomposition of T . If T is a symmetric tensor, and if simple tensors in decompositions are required to be symmetric, then the corresponding smallest value of r is called the symmetric rank of T . A basic result of linear algebra says that these two notions of rank agree for symmetric matrices, and an analogous statement for tensors has become known as Comon's conjecture.Conjecture 1. The symmetric rank of a symmetric tensor equals its rank.Symmetric tensors arise naturally in different applications, so it is an important problem to compute the symmetric ranks and corresponding decompositions, see [2,6,7,11] and references therein. Conjecture 1 received a considerable amount of attention in recent publications, which include [1,3,4,5,6,8,9,11,13,15], but it has been proved in several special cases only. The general form of Conjecture 1 remained open, and the aim of this paper is to construct a counterexample.