Liver alcohol dehydrogenase catalyzes the reaction of NAD+ and benzyl alcohol to form NADH and benzaldehyde by a predominantly ordered reaction. However, enzyme-alcohol binary and abortive ternary complexes form at high concentrations of benzyl alcohol, and benzaldehyde is slowly oxidized to benzoic acid. Steady-state and transient kinetic studies, equilibrium spectrophotometric measurements, product analysis, and kinetic simulations provide estimates of rate constants for a complete mechanism with the following reactions: (1) E<-->E-NAD+<-->E-NAD(+)-RCH2OH<-->E-NADH-RCHO<-->E-NADH<-->E ; (2) E-NADH<-->E-NADH-RCH2OH<-->E-RCH2OH<-->E; (3) E-NAD+<-->E-NAD(+)-RCHO-->E- NADH-RCOOH<-->E-NADH. The internal equilibrium constant for hydrogen transfer determined at 30 degrees C and pH 7 is about 5:1 in favor of E-NAD(+)-RCH2OH and has a complex pH dependence. Benzyl alcohol binds weakly to free enzyme (Kd = 7 mM) and significantly decreases the rates of binding of NAD+ and NADH. The reaction of NAD+ and benzyl alcohol is therefore kinetically ordered, not random. High concentrations of benzyl alcohol (> 1 mM) inhibit turnover by formation of the abortive E-NADH-RCH2-OH complex, which dissociates at 0.3 s-1 as compared to 6.3 s-1 for E-NADH. The oxidation of benzaldehyde by E-NAD+ (Km = 15 mM, V/E = 0.4 s-1) is inefficient relative to the oxidation of benzyl alcohol (Km = 28 microM, V/E = 3.1 s-1) and leads to a dismutation (2RCHO-->RCH2OH + RCOOH) as E-NADH reduces benzaldehyde. The results provide a description of final product distributions for the alternative reactions catalyzed by the multifunctional enzyme.

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