2016
DOI: 10.1090/mcom/3065
|View full text |Cite
|
Sign up to set email alerts
|

Zeros of the dilogarithm

Abstract: We show that the dilogarithm has at most one zero on each branch, that each zero is close to a root of unity, and that they may be found to any precision with Newton's method. This work is motivated by applications to the asymptotics of coefficients in partial fraction decompositions considered by Rademacher.We also survey what is known about zeros of polylogarithms in general. * 2010 Mathematics Subject Classification. 33B30, 30C15 (11P82)

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1

Citation Types

0
1
0

Year Published

2016
2016
2020
2020

Publication Types

Select...
4
1

Relationship

2
3

Authors

Journals

citations
Cited by 6 publications
(1 citation statement)
references
References 17 publications
0
1
0
Order By: Relevance
“…For zeros of zeta functions in the half-plane σ < 0, we have the following research. Peyerimhoff [11] proved that for (fixed) σ < 0, the function Li σ (z) has −⌊σ⌋ simple zeros for z ∈ C \ [1, ∞) and they are all non-positive (see also [10,Section 8]). Spira [15] showed that if σ ≤ −4a−1−2[1−2a] and |t| ≤ 1, then ζ(s, a) = 0 except for zeros on the negative real line, one in each interval (−2n − 4a − 1, −2n − 4a + 1), N ∋ n ≥ 1 − 2a.…”
Section: Introduction and Statement Of Main Resultsmentioning
confidence: 99%
“…For zeros of zeta functions in the half-plane σ < 0, we have the following research. Peyerimhoff [11] proved that for (fixed) σ < 0, the function Li σ (z) has −⌊σ⌋ simple zeros for z ∈ C \ [1, ∞) and they are all non-positive (see also [10,Section 8]). Spira [15] showed that if σ ≤ −4a−1−2[1−2a] and |t| ≤ 1, then ζ(s, a) = 0 except for zeros on the negative real line, one in each interval (−2n − 4a − 1, −2n − 4a + 1), N ∋ n ≥ 1 − 2a.…”
Section: Introduction and Statement Of Main Resultsmentioning
confidence: 99%