2020
DOI: 10.48550/arxiv.2005.07813
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Zero-sum squares in bounded discrepancy {-1,1}-matrices

Abstract: For n ≥ 5, we prove that every n × n {−1, 1}-matrix M = (a ij ) with discrepancy disc(M) = a ij ≤ n contains a zero-sum square except for the diagonal matrix (up to symmetries). Here, a square is a 2 × 2 sub-matrix of M with entries a i,j , a i+s,s , a i,j+s , a i+s,j+s for some s ≥ 1, and the diagonal matrix is a matrix with all entries above the diagonal equal to −1 and all remaining entries equal to 1. In particular, we show that for n ≥ 5 every zero-sum n × n {−1, 1}matrix contains a zero-sum square.

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Cited by 1 publication
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“…The final lemma we will need to prove Theorem 2 is a variation on Claims 1 and 2 from [1]. The main difference between Lemma 5 and the result used by Arévalo, Montejano and Roldán-Pensado is that we will always find a square submatrix.…”
Section: The Submatrixmentioning
confidence: 96%
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“…The final lemma we will need to prove Theorem 2 is a variation on Claims 1 and 2 from [1]. The main difference between Lemma 5 and the result used by Arévalo, Montejano and Roldán-Pensado is that we will always find a square submatrix.…”
Section: The Submatrixmentioning
confidence: 96%
“…Throughout the rest of this paper, we will assume that all submatrices except squares are consecutive submatrices. We start by stating the following lemma from [1] which, starting from a small t ′ -diagonal submatrix M ′ , determines many entries of the matrix M. An example application is shown in Figure 1.…”
Section: Proofmentioning
confidence: 99%
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