2003
DOI: 10.1016/s0022-3093(03)00469-1
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X-ray absorption spectroscopy analysis of formation and structure of Ag nanoparticles in soda-lime silicate glass

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Cited by 33 publications
(20 citation statements)
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“…Due to a changing number of screening electrons [12] this shift is directly related to the valence state. For the glasses used here, the oxidation of Fe 2+ to Fe 3+ was confirmed already as a result of Ag/Na ion exchange and subsequent thermal treatments [13]. This work shows the dependence of the Fe K-edge position on the duration of the ion exchange procedure.…”
Section: Redox Reaction With Iron Ionssupporting
confidence: 64%
“…Due to a changing number of screening electrons [12] this shift is directly related to the valence state. For the glasses used here, the oxidation of Fe 2+ to Fe 3+ was confirmed already as a result of Ag/Na ion exchange and subsequent thermal treatments [13]. This work shows the dependence of the Fe K-edge position on the duration of the ion exchange procedure.…”
Section: Redox Reaction With Iron Ionssupporting
confidence: 64%
“…It seems likely that the reduction of silver with the participation of divalent Fe occurs by the reaction [21] Fe 2+ + Ag + Fe 3+ + Ag 0 . This assumption is supported by the fact that ion exchange reduces the absorption around 9500 cm -1 , arising from Fe 2+ , and increases the absorption near 30000 cm -1 , which is, most likely, the result of Ag 0 formation.…”
Section: Resultsmentioning
confidence: 99%
“…In a layer 128 µm thick, covering most of the ion-exchanged region, the silver content was found to be 1.48 wt % (3.33 × 10 21 ion/cm 3 ), which far exceeds the above estimate of the maximum Ag 0 concentration and, therefore, lends support to it. Assuming that the largest particles are formed if all of the silver ions capable of being reduced under UV irradiation are involved in colloid formation and that the maximum particle diameter is 2R = 8 nm [27] or 7 nm [21], one can estimate the number density of particles n, i.e., the density of colloid formation centers. We find n = 1.69 × 10 15 cm -3 .…”
Section: Resultsmentioning
confidence: 99%
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