2021
DOI: 10.1021/acs.jpca.1c09167
|View full text |Cite
|
Sign up to set email alerts
|

Why Does a B12H12 Icosahedron Need Two Electrons to be Stable: A First-Principles Electron-Correlated Investigation of B12Hn (n = 6, 12) Clusters

Abstract: In this work, we present large-scale electron-correlated computations on various conformers of B12H12 and B12H6 clusters to understand the reasons behind the high stability of dianion icosahedron (Ih ) and cage-like B12H6 geometries. Although the B12 icosahedron is the basic building block in some structures of bulk boron, it is unstable in its free form. Furthermore, its H-passivated entity, i.e., a B12H12 icosahedron, is also unstable in the free form. However, dianion B12H12 has been predicted to be stable … Show more

Help me understand this report
View preprint versions

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1

Citation Types

0
2
0

Year Published

2022
2022
2023
2023

Publication Types

Select...
4
1

Relationship

0
5

Authors

Journals

citations
Cited by 5 publications
(2 citation statements)
references
References 21 publications
(34 reference statements)
0
2
0
Order By: Relevance
“…On the other hand, the binding energy that can ensure the stability of a system can be calculated using the following formula [37] = + −…”
Section: Methodsmentioning
confidence: 99%
“…On the other hand, the binding energy that can ensure the stability of a system can be calculated using the following formula [37] = + −…”
Section: Methodsmentioning
confidence: 99%
“…Their only conclusion was that this cage is unstable, and they did not explore any further. 5 It is well-known that the global minimum of B 12 H 12 2− is an icosahedron, 6 so we have used it as a benchmark to validate our genetic algorithms for exploring PESs. During one of the tests, instead of achieving the icosahedron, we obtained a structure with a three-center-two-electron (3c-2e) B-H 2 bond, which was unexpected.…”
Section: Introductionmentioning
confidence: 99%